2m^2+50=20m

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Solution for 2m^2+50=20m equation:


Simplifying
2m2 + 50 = 20m

Reorder the terms:
50 + 2m2 = 20m

Solving
50 + 2m2 = 20m

Solving for variable 'm'.

Reorder the terms:
50 + -20m + 2m2 = 20m + -20m

Combine like terms: 20m + -20m = 0
50 + -20m + 2m2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(25 + -10m + m2) = 0

Factor a trinomial.
2((5 + -1m)(5 + -1m)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(5 + -1m)' equal to zero and attempt to solve: Simplifying 5 + -1m = 0 Solving 5 + -1m = 0 Move all terms containing m to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1m = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1m = 0 + -5 -1m = 0 + -5 Combine like terms: 0 + -5 = -5 -1m = -5 Divide each side by '-1'. m = 5 Simplifying m = 5

Subproblem 2

Set the factor '(5 + -1m)' equal to zero and attempt to solve: Simplifying 5 + -1m = 0 Solving 5 + -1m = 0 Move all terms containing m to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1m = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1m = 0 + -5 -1m = 0 + -5 Combine like terms: 0 + -5 = -5 -1m = -5 Divide each side by '-1'. m = 5 Simplifying m = 5

Solution

m = {5, 5}

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